The Bishop and the Vicar meet three bellringers and the Bishop asks how old they are.
The Vicar replies that the three ages multiplied together is 2,450 and when added together the result is twice the Bishop's age.
The Bishop says that is not enough information to solve the problem so the Vicar tells him that he (the Vicar) is older than all of them.

That is enough information for the Bishop to solve his problem ... your problem is ... how old is the Vicar?

My solution.

2450=2x5x5x7x7

So the possible ages are:

5 10 49 giving 5+10+49=64 so bishop:32
5 14 35 giving 5+14+35=54 so bishop:27
7 10 35 giving 7+10+35=52 so bishop:26
7 14 25 giving 7+14+25=46 so bishop:23
7 7 50 giving 7+7+50=64 so bishop:32

Since the Bishop can't work it out, he must be 32.
So the vicar must be 50 to distinguish between:

5+10+49=64 so bishop:32 and 7+7+50=64 so bishop:32.