The Bishop and the Vicar meet three bellringers and the Bishop asks how
old they are.

The Vicar replies that the three ages multiplied together is 2,450
and when added together the result is twice
the Bishop's age.

The Bishop says that is not enough information to solve the problem
so the Vicar tells him that he (the Vicar) is older than all of them.

That is enough information for the Bishop to solve
his problem ... your problem is ... how old is the Vicar?

My solution.

2450=2x5x5x7x7 So the possible ages are: 5 10 49 giving 5+10+49=64 so bishop:32 5 14 35 giving 5+14+35=54 so bishop:27 7 10 35 giving 7+10+35=52 so bishop:26 7 14 25 giving 7+14+25=46 so bishop:23 7 7 50 giving 7+7+50=64 so bishop:32 Since the Bishop can't work it out, he must be 32. So the vicar must be50to distinguish between: 5+10+49=64 so bishop:32 and 7+7+50=64 so bishop:32.